3(4y-2)=10

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Solution for 3(4y-2)=10 equation: 



3(4y-2)=10

We move all terms to the left:

3(4y-2)-(10)=0

We multiply parentheses

12y-6-10=0

We add all the numbers together, and all the variables

12y-16=0

We move all terms containing y to the left, all other terms to the right

12y=16

y=16/12

y=1+1/3

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