3(4y-5)=11(y-4)

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Solution for 3(4y-5)=11(y-4) equation: 



3(4y-5)=11(y-4)

We move all terms to the left:

3(4y-5)-(11(y-4))=0

We multiply parentheses

12y-(11(y-4))-15=0



We calculate terms in parentheses: -(11(y-4)), so:

11(y-4)

We multiply parentheses

11y-44

Back to the equation:

-(11y-44)



We get rid of parentheses

12y-11y+44-15=0

We add all the numbers together, and all the variables

y+29=0

We move all terms containing y to the left, all other terms to the right

y=-29

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