3(4y-6)=14+16

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Solution for 3(4y-6)=14+16 equation:



3(4y-6)=14+16
We move all terms to the left:
3(4y-6)-(14+16)=0
We add all the numbers together, and all the variables
3(4y-6)-30=0
We multiply parentheses
12y-18-30=0
We add all the numbers together, and all the variables
12y-48=0
We move all terms containing y to the left, all other terms to the right
12y=48
y=48/12
y=4

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