3(4y-6)=14+16

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Solution for 3(4y-6)=14+16 equation: 



3(4y-6)=14+16

We move all terms to the left:

3(4y-6)-(14+16)=0

We add all the numbers together, and all the variables

3(4y-6)-30=0

We multiply parentheses

12y-18-30=0

We add all the numbers together, and all the variables

12y-48=0

We move all terms containing y to the left, all other terms to the right

12y=48

y=48/12

y=4

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