3(4z+1)-6=105

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Solution for 3(4z+1)-6=105 equation: 



3(4z+1)-6=105

We move all terms to the left:

3(4z+1)-6-(105)=0

We add all the numbers together, and all the variables

3(4z+1)-111=0

We multiply parentheses

12z+3-111=0

We add all the numbers together, and all the variables

12z-108=0

We move all terms containing z to the left, all other terms to the right

12z=108

z=108/12

z=9

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