3(4z+1)-7=80

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Solution for 3(4z+1)-7=80 equation:


Simplifying
3(4z + 1) + -7 = 80

Reorder the terms:
3(1 + 4z) + -7 = 80
(1 * 3 + 4z * 3) + -7 = 80
(3 + 12z) + -7 = 80

Reorder the terms:
3 + -7 + 12z = 80

Combine like terms: 3 + -7 = -4
-4 + 12z = 80

Solving
-4 + 12z = 80

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 12z = 80 + 4

Combine like terms: -4 + 4 = 0
0 + 12z = 80 + 4
12z = 80 + 4

Combine like terms: 80 + 4 = 84
12z = 84

Divide each side by '12'.
z = 7

Simplifying
z = 7

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