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3(4z+1)-9z=6(2-z)
We move all terms to the left:
3(4z+1)-9z-(6(2-z))=0
We add all the numbers together, and all the variables
3(4z+1)-9z-(6(-1z+2))=0
We add all the numbers together, and all the variables
-9z+3(4z+1)-(6(-1z+2))=0
We multiply parentheses
-9z+12z-(6(-1z+2))+3=0
We calculate terms in parentheses: -(6(-1z+2)), so:We add all the numbers together, and all the variables
6(-1z+2)
We multiply parentheses
-6z+12
Back to the equation:
-(-6z+12)
3z-(-6z+12)+3=0
We get rid of parentheses
3z+6z-12+3=0
We add all the numbers together, and all the variables
9z-9=0
We move all terms containing z to the left, all other terms to the right
9z=9
z=9/9
z=1
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