3(4z+10)=112

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Solution for 3(4z+10)=112 equation: 



3(4z+10)=112

We move all terms to the left:

3(4z+10)-(112)=0

We multiply parentheses

12z+30-112=0

We add all the numbers together, and all the variables

12z-82=0

We move all terms containing z to the left, all other terms to the right

12z=82

z=82/12

z=6+5/6

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