3(4z-(7))=-21+12z

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Solution for 3(4z-(7))=-21+12z equation: 


Simplifying
3(4z + -1(7)) = -21 + 12z

Multiply -1 * 7
3(4z + -7) = -21 + 12z

Reorder the terms:
3(-7 + 4z) = -21 + 12z
(-7 * 3 + 4z * 3) = -21 + 12z
(-21 + 12z) = -21 + 12z

Add '21' to each side of the equation.
-21 + 21 + 12z = -21 + 21 + 12z

Combine like terms: -21 + 21 = 0
0 + 12z = -21 + 21 + 12z
12z = -21 + 21 + 12z

Combine like terms: -21 + 21 = 0
12z = 0 + 12z
12z = 12z

Add '-12z' to each side of the equation.
12z + -12z = 12z + -12z

Combine like terms: 12z + -12z = 0
0 = 12z + -12z

Combine like terms: 12z + -12z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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