3(4z-1)-2(z+1)=2(z+1)

Solution for 3(4z-1)-2(z+1)=2(z+1) equation:

Simplifying
3(4z + -1) + -2(z + 1) = 2(z + 1)

Reorder the terms:
3(-1 + 4z) + -2(z + 1) = 2(z + 1)
(-1 * 3 + 4z * 3) + -2(z + 1) = 2(z + 1)
(-3 + 12z) + -2(z + 1) = 2(z + 1)

Reorder the terms:
-3 + 12z + -2(1 + z) = 2(z + 1)
-3 + 12z + (1 * -2 + z * -2) = 2(z + 1)
-3 + 12z + (-2 + -2z) = 2(z + 1)

Reorder the terms:
-3 + -2 + 12z + -2z = 2(z + 1)

Combine like terms: -3 + -2 = -5
-5 + 12z + -2z = 2(z + 1)

Combine like terms: 12z + -2z = 10z
-5 + 10z = 2(z + 1)

Reorder the terms:
-5 + 10z = 2(1 + z)
-5 + 10z = (1 * 2 + z * 2)
-5 + 10z = (2 + 2z)

Solving
-5 + 10z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-5 + 10z + -2z = 2 + 2z + -2z

Combine like terms: 10z + -2z = 8z
-5 + 8z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-5 + 8z = 2 + 0
-5 + 8z = 2

Add '5' to each side of the equation.
-5 + 5 + 8z = 2 + 5

Combine like terms: -5 + 5 = 0
0 + 8z = 2 + 5
8z = 2 + 5

Combine like terms: 2 + 5 = 7
8z = 7

Divide each side by '8'.
z = 0.875

Simplifying
z = 0.875