3(4z-1)-2(z+2)=2(z+1)

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Solution for 3(4z-1)-2(z+2)=2(z+1) equation:


Simplifying
3(4z + -1) + -2(z + 2) = 2(z + 1)

Reorder the terms:
3(-1 + 4z) + -2(z + 2) = 2(z + 1)
(-1 * 3 + 4z * 3) + -2(z + 2) = 2(z + 1)
(-3 + 12z) + -2(z + 2) = 2(z + 1)

Reorder the terms:
-3 + 12z + -2(2 + z) = 2(z + 1)
-3 + 12z + (2 * -2 + z * -2) = 2(z + 1)
-3 + 12z + (-4 + -2z) = 2(z + 1)

Reorder the terms:
-3 + -4 + 12z + -2z = 2(z + 1)

Combine like terms: -3 + -4 = -7
-7 + 12z + -2z = 2(z + 1)

Combine like terms: 12z + -2z = 10z
-7 + 10z = 2(z + 1)

Reorder the terms:
-7 + 10z = 2(1 + z)
-7 + 10z = (1 * 2 + z * 2)
-7 + 10z = (2 + 2z)

Solving
-7 + 10z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-7 + 10z + -2z = 2 + 2z + -2z

Combine like terms: 10z + -2z = 8z
-7 + 8z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-7 + 8z = 2 + 0
-7 + 8z = 2

Add '7' to each side of the equation.
-7 + 7 + 8z = 2 + 7

Combine like terms: -7 + 7 = 0
0 + 8z = 2 + 7
8z = 2 + 7

Combine like terms: 2 + 7 = 9
8z = 9

Divide each side by '8'.
z = 1.125

Simplifying
z = 1.125

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