3(4z-1)-2(z+2)=6(z+1)

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Solution for 3(4z-1)-2(z+2)=6(z+1) equation:


3(4z-1)-2(z+2)=6(z+1)

We simplify the equation to the form, which is simple to understand
3(4z-1)-2(z+2)=6(z+1)

Reorder the terms in parentheses
+(+12z-3)-2*(z+2)=6*(z+1)

Remove unnecessary parentheses
+12z-3-2+*(+z+2+)=+6+*(+z+1+)

Reorder the terms in parentheses
+12z-3+(-2z-4)=6*(z+1)

Remove unnecessary parentheses
+12z-3-2z-4=+6+*(+z+1+)

Reorder the terms in parentheses
+12z-3-2z-4=+(+6z+6)

Remove unnecessary parentheses
+12z-3-2z-4=+6z+6

We move all terms containing z to the left and all other terms to the right.
+12z-2z-6z=+6+3+4

We simplify left and right side of the equation.
+4z=+13

We divide both sides of the equation by 4 to get z.
z=3.25

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