3(4z-1)-3(z+1)=2(z+1)

Solution for 3(4z-1)-3(z+1)=2(z+1) equation:

Simplifying
3(4z + -1) + -3(z + 1) = 2(z + 1)

Reorder the terms:
3(-1 + 4z) + -3(z + 1) = 2(z + 1)
(-1 * 3 + 4z * 3) + -3(z + 1) = 2(z + 1)
(-3 + 12z) + -3(z + 1) = 2(z + 1)

Reorder the terms:
-3 + 12z + -3(1 + z) = 2(z + 1)
-3 + 12z + (1 * -3 + z * -3) = 2(z + 1)
-3 + 12z + (-3 + -3z) = 2(z + 1)

Reorder the terms:
-3 + -3 + 12z + -3z = 2(z + 1)

Combine like terms: -3 + -3 = -6
-6 + 12z + -3z = 2(z + 1)

Combine like terms: 12z + -3z = 9z
-6 + 9z = 2(z + 1)

Reorder the terms:
-6 + 9z = 2(1 + z)
-6 + 9z = (1 * 2 + z * 2)
-6 + 9z = (2 + 2z)

Solving
-6 + 9z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-6 + 9z + -2z = 2 + 2z + -2z

Combine like terms: 9z + -2z = 7z
-6 + 7z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-6 + 7z = 2 + 0
-6 + 7z = 2

Add '6' to each side of the equation.
-6 + 6 + 7z = 2 + 6

Combine like terms: -6 + 6 = 0
0 + 7z = 2 + 6
7z = 2 + 6

Combine like terms: 2 + 6 = 8
7z = 8

Divide each side by '7'.
z = 1.142857143

Simplifying
z = 1.142857143