3(4z-1)-3(z+4)=2(z+1)

Solution for 3(4z-1)-3(z+4)=2(z+1) equation:

Simplifying
3(4z + -1) + -3(z + 4) = 2(z + 1)

Reorder the terms:
3(-1 + 4z) + -3(z + 4) = 2(z + 1)
(-1 * 3 + 4z * 3) + -3(z + 4) = 2(z + 1)
(-3 + 12z) + -3(z + 4) = 2(z + 1)

Reorder the terms:
-3 + 12z + -3(4 + z) = 2(z + 1)
-3 + 12z + (4 * -3 + z * -3) = 2(z + 1)
-3 + 12z + (-12 + -3z) = 2(z + 1)

Reorder the terms:
-3 + -12 + 12z + -3z = 2(z + 1)

Combine like terms: -3 + -12 = -15
-15 + 12z + -3z = 2(z + 1)

Combine like terms: 12z + -3z = 9z
-15 + 9z = 2(z + 1)

Reorder the terms:
-15 + 9z = 2(1 + z)
-15 + 9z = (1 * 2 + z * 2)
-15 + 9z = (2 + 2z)

Solving
-15 + 9z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-15 + 9z + -2z = 2 + 2z + -2z

Combine like terms: 9z + -2z = 7z
-15 + 7z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-15 + 7z = 2 + 0
-15 + 7z = 2

Add '15' to each side of the equation.
-15 + 15 + 7z = 2 + 15

Combine like terms: -15 + 15 = 0
0 + 7z = 2 + 15
7z = 2 + 15

Combine like terms: 2 + 15 = 17
7z = 17

Divide each side by '7'.
z = 2.428571429

Simplifying
z = 2.428571429