3(4z-1)-4(z+2)=4(z+1)

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Solution for 3(4z-1)-4(z+2)=4(z+1) equation:


Simplifying
3(4z + -1) + -4(z + 2) = 4(z + 1)

Reorder the terms:
3(-1 + 4z) + -4(z + 2) = 4(z + 1)
(-1 * 3 + 4z * 3) + -4(z + 2) = 4(z + 1)
(-3 + 12z) + -4(z + 2) = 4(z + 1)

Reorder the terms:
-3 + 12z + -4(2 + z) = 4(z + 1)
-3 + 12z + (2 * -4 + z * -4) = 4(z + 1)
-3 + 12z + (-8 + -4z) = 4(z + 1)

Reorder the terms:
-3 + -8 + 12z + -4z = 4(z + 1)

Combine like terms: -3 + -8 = -11
-11 + 12z + -4z = 4(z + 1)

Combine like terms: 12z + -4z = 8z
-11 + 8z = 4(z + 1)

Reorder the terms:
-11 + 8z = 4(1 + z)
-11 + 8z = (1 * 4 + z * 4)
-11 + 8z = (4 + 4z)

Solving
-11 + 8z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-11 + 8z + -4z = 4 + 4z + -4z

Combine like terms: 8z + -4z = 4z
-11 + 4z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-11 + 4z = 4 + 0
-11 + 4z = 4

Add '11' to each side of the equation.
-11 + 11 + 4z = 4 + 11

Combine like terms: -11 + 11 = 0
0 + 4z = 4 + 11
4z = 4 + 11

Combine like terms: 4 + 11 = 15
4z = 15

Divide each side by '4'.
z = 3.75

Simplifying
z = 3.75

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