3(4z-1)-4(z+2)=6(z+1)

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Solution for 3(4z-1)-4(z+2)=6(z+1) equation:


Simplifying
3(4z + -1) + -4(z + 2) = 6(z + 1)

Reorder the terms:
3(-1 + 4z) + -4(z + 2) = 6(z + 1)
(-1 * 3 + 4z * 3) + -4(z + 2) = 6(z + 1)
(-3 + 12z) + -4(z + 2) = 6(z + 1)

Reorder the terms:
-3 + 12z + -4(2 + z) = 6(z + 1)
-3 + 12z + (2 * -4 + z * -4) = 6(z + 1)
-3 + 12z + (-8 + -4z) = 6(z + 1)

Reorder the terms:
-3 + -8 + 12z + -4z = 6(z + 1)

Combine like terms: -3 + -8 = -11
-11 + 12z + -4z = 6(z + 1)

Combine like terms: 12z + -4z = 8z
-11 + 8z = 6(z + 1)

Reorder the terms:
-11 + 8z = 6(1 + z)
-11 + 8z = (1 * 6 + z * 6)
-11 + 8z = (6 + 6z)

Solving
-11 + 8z = 6 + 6z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6z' to each side of the equation.
-11 + 8z + -6z = 6 + 6z + -6z

Combine like terms: 8z + -6z = 2z
-11 + 2z = 6 + 6z + -6z

Combine like terms: 6z + -6z = 0
-11 + 2z = 6 + 0
-11 + 2z = 6

Add '11' to each side of the equation.
-11 + 11 + 2z = 6 + 11

Combine like terms: -11 + 11 = 0
0 + 2z = 6 + 11
2z = 6 + 11

Combine like terms: 6 + 11 = 17
2z = 17

Divide each side by '2'.
z = 8.5

Simplifying
z = 8.5

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