3(4z-1)-4(z+6)=2(z+1)

Solution for 3(4z-1)-4(z+6)=2(z+1) equation:

Simplifying
3(4z + -1) + -4(z + 6) = 2(z + 1)

Reorder the terms:
3(-1 + 4z) + -4(z + 6) = 2(z + 1)
(-1 * 3 + 4z * 3) + -4(z + 6) = 2(z + 1)
(-3 + 12z) + -4(z + 6) = 2(z + 1)

Reorder the terms:
-3 + 12z + -4(6 + z) = 2(z + 1)
-3 + 12z + (6 * -4 + z * -4) = 2(z + 1)
-3 + 12z + (-24 + -4z) = 2(z + 1)

Reorder the terms:
-3 + -24 + 12z + -4z = 2(z + 1)

Combine like terms: -3 + -24 = -27
-27 + 12z + -4z = 2(z + 1)

Combine like terms: 12z + -4z = 8z
-27 + 8z = 2(z + 1)

Reorder the terms:
-27 + 8z = 2(1 + z)
-27 + 8z = (1 * 2 + z * 2)
-27 + 8z = (2 + 2z)

Solving
-27 + 8z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-27 + 8z + -2z = 2 + 2z + -2z

Combine like terms: 8z + -2z = 6z
-27 + 6z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-27 + 6z = 2 + 0
-27 + 6z = 2

Add '27' to each side of the equation.
-27 + 27 + 6z = 2 + 27

Combine like terms: -27 + 27 = 0
0 + 6z = 2 + 27
6z = 2 + 27

Combine like terms: 2 + 27 = 29
6z = 29

Divide each side by '6'.
z = 4.833333333

Simplifying
z = 4.833333333