3(4z-1)-5(z+3)=(z+1)

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Solution for 3(4z-1)-5(z+3)=(z+1) equation:


Simplifying
3(4z + -1) + -5(z + 3) = (z + 1)

Reorder the terms:
3(-1 + 4z) + -5(z + 3) = (z + 1)
(-1 * 3 + 4z * 3) + -5(z + 3) = (z + 1)
(-3 + 12z) + -5(z + 3) = (z + 1)

Reorder the terms:
-3 + 12z + -5(3 + z) = (z + 1)
-3 + 12z + (3 * -5 + z * -5) = (z + 1)
-3 + 12z + (-15 + -5z) = (z + 1)

Reorder the terms:
-3 + -15 + 12z + -5z = (z + 1)

Combine like terms: -3 + -15 = -18
-18 + 12z + -5z = (z + 1)

Combine like terms: 12z + -5z = 7z
-18 + 7z = (z + 1)

Reorder the terms:
-18 + 7z = (1 + z)

Remove parenthesis around (1 + z)
-18 + 7z = 1 + z

Solving
-18 + 7z = 1 + z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
-18 + 7z + -1z = 1 + z + -1z

Combine like terms: 7z + -1z = 6z
-18 + 6z = 1 + z + -1z

Combine like terms: z + -1z = 0
-18 + 6z = 1 + 0
-18 + 6z = 1

Add '18' to each side of the equation.
-18 + 18 + 6z = 1 + 18

Combine like terms: -18 + 18 = 0
0 + 6z = 1 + 18
6z = 1 + 18

Combine like terms: 1 + 18 = 19
6z = 19

Divide each side by '6'.
z = 3.166666667

Simplifying
z = 3.166666667

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