3(5)=(1/2)(6x+24)

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Solution for 3(5)=(1/2)(6x+24) equation: 



3(5)=(1/2)(6x+24)

We move all terms to the left:

3(5)-((1/2)(6x+24))=0



Domain of the equation: 2)(6x+24))!=0

x∈R



We add all the numbers together, and all the variables

-((+1/2)(6x+24))+35=0

We multiply parentheses ..

-((+6x^2+1/2*24))+35=0

We multiply all the terms by the denominator


-((+6x^2+1+35*2*24))=0



We calculate terms in parentheses: -((+6x^2+1+35*2*24)), so:

(+6x^2+1+35*2*24)

We get rid of parentheses

6x^2+1+35*2*24

We add all the numbers together, and all the variables

6x^2+1681

Back to the equation:

-(6x^2+1681)



We get rid of parentheses

-6x^2-1681=0

a = -6; b = 0; c = -1681;
Δ = b2-4ac
Δ = 02-4·(-6)·(-1681)
Δ = -40344
Delta is less than zero, so there is no solution for the equation

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