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3(5+3x)-6(2x-4)=12x+19
We move all terms to the left:
3(5+3x)-6(2x-4)-(12x+19)=0
We add all the numbers together, and all the variables
3(3x+5)-6(2x-4)-(12x+19)=0
We multiply parentheses
9x-12x-(12x+19)+15+24=0
We get rid of parentheses
9x-12x-12x-19+15+24=0
We add all the numbers together, and all the variables
-15x+20=0
We move all terms containing x to the left, all other terms to the right
-15x=-20
x=-20/-15
x=1+1/3
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