3(5+c)=2(c-1)

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Solution for 3(5+c)=2(c-1) equation:


Simplifying
3(5 + c) = 2(c + -1)
(5 * 3 + c * 3) = 2(c + -1)
(15 + 3c) = 2(c + -1)

Reorder the terms:
15 + 3c = 2(-1 + c)
15 + 3c = (-1 * 2 + c * 2)
15 + 3c = (-2 + 2c)

Solving
15 + 3c = -2 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
15 + 3c + -2c = -2 + 2c + -2c

Combine like terms: 3c + -2c = 1c
15 + 1c = -2 + 2c + -2c

Combine like terms: 2c + -2c = 0
15 + 1c = -2 + 0
15 + 1c = -2

Add '-15' to each side of the equation.
15 + -15 + 1c = -2 + -15

Combine like terms: 15 + -15 = 0
0 + 1c = -2 + -15
1c = -2 + -15

Combine like terms: -2 + -15 = -17
1c = -17

Divide each side by '1'.
c = -17

Simplifying
c = -17

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