3(5+j)=2(3j-6)

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Solution for 3(5+j)=2(3j-6) equation: 



3(5+j)=2(3j-6)

We move all terms to the left:

3(5+j)-(2(3j-6))=0

We add all the numbers together, and all the variables

3(j+5)-(2(3j-6))=0

We multiply parentheses

3j-(2(3j-6))+15=0



We calculate terms in parentheses: -(2(3j-6)), so:

2(3j-6)

We multiply parentheses

6j-12

Back to the equation:

-(6j-12)



We get rid of parentheses

3j-6j+12+15=0

We add all the numbers together, and all the variables

-3j+27=0

We move all terms containing j to the left, all other terms to the right

-3j=-27

j=-27/-3

j=+9

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