3(5+x)=2(6x+1)+3(3+4x)

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Solution for 3(5+x)=2(6x+1)+3(3+4x) equation: 



3(5+x)=2(6x+1)+3(3+4x)

We move all terms to the left:

3(5+x)-(2(6x+1)+3(3+4x))=0

We add all the numbers together, and all the variables

3(x+5)-(2(6x+1)+3(4x+3))=0

We multiply parentheses

3x-(2(6x+1)+3(4x+3))+15=0



We calculate terms in parentheses: -(2(6x+1)+3(4x+3)), so:

2(6x+1)+3(4x+3)

We multiply parentheses

12x+12x+2+9

We add all the numbers together, and all the variables

24x+11

Back to the equation:

-(24x+11)



We get rid of parentheses

3x-24x-11+15=0

We add all the numbers together, and all the variables

-21x+4=0

We move all terms containing x to the left, all other terms to the right

-21x=-4

x=-4/-21

x=4/21

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