3(5+x)=2(6x+1)+3(3+4x)

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Solution for 3(5+x)=2(6x+1)+3(3+4x) equation:



3(5+x)=2(6x+1)+3(3+4x)
We move all terms to the left:
3(5+x)-(2(6x+1)+3(3+4x))=0
We add all the numbers together, and all the variables
3(x+5)-(2(6x+1)+3(4x+3))=0
We multiply parentheses
3x-(2(6x+1)+3(4x+3))+15=0
We calculate terms in parentheses: -(2(6x+1)+3(4x+3)), so:
2(6x+1)+3(4x+3)
We multiply parentheses
12x+12x+2+9
We add all the numbers together, and all the variables
24x+11
Back to the equation:
-(24x+11)
We get rid of parentheses
3x-24x-11+15=0
We add all the numbers together, and all the variables
-21x+4=0
We move all terms containing x to the left, all other terms to the right
-21x=-4
x=-4/-21
x=4/21

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