3(5-2f)=4-(4f-1)

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Solution for 3(5-2f)=4-(4f-1) equation: 



3(5-2f)=4-(4f-1)

We move all terms to the left:

3(5-2f)-(4-(4f-1))=0

We add all the numbers together, and all the variables

3(-2f+5)-(4-(4f-1))=0

We multiply parentheses

-6f-(4-(4f-1))+15=0



We calculate terms in parentheses: -(4-(4f-1)), so:

4-(4f-1)

determiningTheFunctionDomain
-(4f-1)+4

We get rid of parentheses

-4f+1+4

We add all the numbers together, and all the variables

-4f+5

Back to the equation:

-(-4f+5)



We get rid of parentheses

-6f+4f-5+15=0

We add all the numbers together, and all the variables

-2f+10=0

We move all terms containing f to the left, all other terms to the right

-2f=-10

f=-10/-2

f=+5

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