3(5-2x)+7=6-2(x-2)

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Solution for 3(5-2x)+7=6-2(x-2) equation: 



3(5-2x)+7=6-2(x-2)

We move all terms to the left:

3(5-2x)+7-(6-2(x-2))=0

We add all the numbers together, and all the variables

3(-2x+5)-(6-2(x-2))+7=0

We multiply parentheses

-6x-(6-2(x-2))+15+7=0



We calculate terms in parentheses: -(6-2(x-2)), so:

6-2(x-2)

determiningTheFunctionDomain
-2(x-2)+6

We multiply parentheses

-2x+4+6

We add all the numbers together, and all the variables

-2x+10

Back to the equation:

-(-2x+10)



We add all the numbers together, and all the variables

-6x-(-2x+10)+22=0

We get rid of parentheses

-6x+2x-10+22=0

We add all the numbers together, and all the variables

-4x+12=0

We move all terms containing x to the left, all other terms to the right

-4x=-12

x=-12/-4

x=+3

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