3(5-2x)-(8x+7)=6x+4-2(x-1)

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Solution for 3(5-2x)-(8x+7)=6x+4-2(x-1) equation: 



3(5-2x)-(8x+7)=6x+4-2(x-1)

We move all terms to the left:

3(5-2x)-(8x+7)-(6x+4-2(x-1))=0

We add all the numbers together, and all the variables

3(-2x+5)-(8x+7)-(6x+4-2(x-1))=0

We multiply parentheses

-6x-(8x+7)-(6x+4-2(x-1))+15=0

We get rid of parentheses

-6x-8x-(6x+4-2(x-1))-7+15=0



We calculate terms in parentheses: -(6x+4-2(x-1)), so:

6x+4-2(x-1)

determiningTheFunctionDomain
6x-2(x-1)+4

We multiply parentheses

6x-2x+2+4

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

-14x-(4x+6)+8=0

We get rid of parentheses

-14x-4x-6+8=0

We add all the numbers together, and all the variables

-18x+2=0

We move all terms containing x to the left, all other terms to the right

-18x=-2

x=-2/-18

x=1/9

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