3(5-2x)=3x-40-4x

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Solution for 3(5-2x)=3x-40-4x equation: 



3(5-2x)=3x-40-4x

We move all terms to the left:

3(5-2x)-(3x-40-4x)=0

We add all the numbers together, and all the variables

3(-2x+5)-(-1x-40)=0

We multiply parentheses

-6x-(-1x-40)+15=0

We get rid of parentheses

-6x+1x+40+15=0

We add all the numbers together, and all the variables

-5x+55=0

We move all terms containing x to the left, all other terms to the right

-5x=-55

x=-55/-5

x=+11

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