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3(5-3x)=3(2x+1)
We move all terms to the left:
3(5-3x)-(3(2x+1))=0
We add all the numbers together, and all the variables
3(-3x+5)-(3(2x+1))=0
We multiply parentheses
-9x-(3(2x+1))+15=0
We calculate terms in parentheses: -(3(2x+1)), so:We get rid of parentheses
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
-9x-6x-3+15=0
We add all the numbers together, and all the variables
-15x+12=0
We move all terms containing x to the left, all other terms to the right
-15x=-12
x=-12/-15
x=4/5
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