3(5-a)-27=17a-4(3+5a)

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Solution for 3(5-a)-27=17a-4(3+5a) equation:


Simplifying
3(5 + -1a) + -27 = 17a + -4(3 + 5a)
(5 * 3 + -1a * 3) + -27 = 17a + -4(3 + 5a)
(15 + -3a) + -27 = 17a + -4(3 + 5a)

Reorder the terms:
15 + -27 + -3a = 17a + -4(3 + 5a)

Combine like terms: 15 + -27 = -12
-12 + -3a = 17a + -4(3 + 5a)
-12 + -3a = 17a + (3 * -4 + 5a * -4)
-12 + -3a = 17a + (-12 + -20a)

Reorder the terms:
-12 + -3a = -12 + 17a + -20a

Combine like terms: 17a + -20a = -3a
-12 + -3a = -12 + -3a

Add '12' to each side of the equation.
-12 + 12 + -3a = -12 + 12 + -3a

Combine like terms: -12 + 12 = 0
0 + -3a = -12 + 12 + -3a
-3a = -12 + 12 + -3a

Combine like terms: -12 + 12 = 0
-3a = 0 + -3a
-3a = -3a

Add '3a' to each side of the equation.
-3a + 3a = -3a + 3a

Combine like terms: -3a + 3a = 0
0 = -3a + 3a

Combine like terms: -3a + 3a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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