3(5-c)-23=17c-4(2+5c)

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Solution for 3(5-c)-23=17c-4(2+5c) equation: 



3(5-c)-23=17c-4(2+5c)

We move all terms to the left:

3(5-c)-23-(17c-4(2+5c))=0

We add all the numbers together, and all the variables

3(-1c+5)-(17c-4(5c+2))-23=0

We multiply parentheses

-3c-(17c-4(5c+2))+15-23=0



We calculate terms in parentheses: -(17c-4(5c+2)), so:

17c-4(5c+2)

We multiply parentheses

17c-20c-8

We add all the numbers together, and all the variables

-3c-8

Back to the equation:

-(-3c-8)



We add all the numbers together, and all the variables

-3c-(-3c-8)-8=0

We get rid of parentheses

-3c+3c+8-8=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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