3(5-c)-23=21c-4(2+6c)

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Solution for 3(5-c)-23=21c-4(2+6c) equation:


Simplifying
3(5 + -1c) + -23 = 21c + -4(2 + 6c)
(5 * 3 + -1c * 3) + -23 = 21c + -4(2 + 6c)
(15 + -3c) + -23 = 21c + -4(2 + 6c)

Reorder the terms:
15 + -23 + -3c = 21c + -4(2 + 6c)

Combine like terms: 15 + -23 = -8
-8 + -3c = 21c + -4(2 + 6c)
-8 + -3c = 21c + (2 * -4 + 6c * -4)
-8 + -3c = 21c + (-8 + -24c)

Reorder the terms:
-8 + -3c = -8 + 21c + -24c

Combine like terms: 21c + -24c = -3c
-8 + -3c = -8 + -3c

Add '8' to each side of the equation.
-8 + 8 + -3c = -8 + 8 + -3c

Combine like terms: -8 + 8 = 0
0 + -3c = -8 + 8 + -3c
-3c = -8 + 8 + -3c

Combine like terms: -8 + 8 = 0
-3c = 0 + -3c
-3c = -3c

Add '3c' to each side of the equation.
-3c + 3c = -3c + 3c

Combine like terms: -3c + 3c = 0
0 = -3c + 3c

Combine like terms: -3c + 3c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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