3(5-c)-27=17c-4(3+5c)

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Solution for 3(5-c)-27=17c-4(3+5c) equation:



3(5-c)-27=17c-4(3+5c)
We move all terms to the left:
3(5-c)-27-(17c-4(3+5c))=0
We add all the numbers together, and all the variables
3(-1c+5)-(17c-4(5c+3))-27=0
We multiply parentheses
-3c-(17c-4(5c+3))+15-27=0
We calculate terms in parentheses: -(17c-4(5c+3)), so:
17c-4(5c+3)
We multiply parentheses
17c-20c-12
We add all the numbers together, and all the variables
-3c-12
Back to the equation:
-(-3c-12)
We add all the numbers together, and all the variables
-3c-(-3c-12)-12=0
We get rid of parentheses
-3c+3c+12-12=0
We add all the numbers together, and all the variables
=0
c=0/1
c=0

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