3(5-c)=-2(2c+1)

Solution for 3(5-c)=-2(2c+1) equation:

3(5-c)=-2(2c+1)

We move all terms to the left:

3(5-c)-(-2(2c+1))=0

We add all the numbers together, and all the variables

3(-1c+5)-(-2(2c+1))=0

We multiply parentheses

-3c-(-2(2c+1))+15=0


We calculate terms in parentheses: -(-2(2c+1)), so:

-2(2c+1)

We multiply parentheses

-4c-2

Back to the equation:

-(-4c-2)


We get rid of parentheses

-3c+4c+2+15=0

We add all the numbers together, and all the variables

c+17=0

We move all terms containing c to the left, all other terms to the right

c=-17