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3(5-t)=2-(2-2t)
We move all terms to the left:
3(5-t)-(2-(2-2t))=0
We add all the numbers together, and all the variables
3(-1t+5)-(2-(-2t+2))=0
We multiply parentheses
-3t-(2-(-2t+2))+15=0
We calculate terms in parentheses: -(2-(-2t+2)), so:We add all the numbers together, and all the variables
2-(-2t+2)
determiningTheFunctionDomain -(-2t+2)+2
We get rid of parentheses
2t-2+2
We add all the numbers together, and all the variables
2t
Back to the equation:
-(2t)
-5t+15=0
We move all terms containing t to the left, all other terms to the right
-5t=-15
t=-15/-5
t=+3
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