3(5-x)+2(4x-3)=2+4(2-x)+6x

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Solution for 3(5-x)+2(4x-3)=2+4(2-x)+6x equation:



3(5-x)+2(4x-3)=2+4(2-x)+6x
We move all terms to the left:
3(5-x)+2(4x-3)-(2+4(2-x)+6x)=0
We add all the numbers together, and all the variables
3(-1x+5)+2(4x-3)-(2+4(-1x+2)+6x)=0
We multiply parentheses
-3x+8x-(2+4(-1x+2)+6x)+15-6=0
We calculate terms in parentheses: -(2+4(-1x+2)+6x), so:
2+4(-1x+2)+6x
determiningTheFunctionDomain 4(-1x+2)+6x+2
We add all the numbers together, and all the variables
6x+4(-1x+2)+2
We multiply parentheses
6x-4x+8+2
We add all the numbers together, and all the variables
2x+10
Back to the equation:
-(2x+10)
We add all the numbers together, and all the variables
5x-(2x+10)+9=0
We get rid of parentheses
5x-2x-10+9=0
We add all the numbers together, and all the variables
3x-1=0
We move all terms containing x to the left, all other terms to the right
3x=1
x=1/3
x=1/3

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