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3(5-x)4x=18
We move all terms to the left:
3(5-x)4x-(18)=0
We add all the numbers together, and all the variables
3(-1x+5)4x-18=0
We multiply parentheses
-12x^2+60x-18=0
a = -12; b = 60; c = -18;
Δ = b2-4ac
Δ = 602-4·(-12)·(-18)
Δ = 2736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2736}=\sqrt{144*19}=\sqrt{144}*\sqrt{19}=12\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-12\sqrt{19}}{2*-12}=\frac{-60-12\sqrt{19}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+12\sqrt{19}}{2*-12}=\frac{-60+12\sqrt{19}}{-24} $
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