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3(5-x)=(x-1)=3
We move all terms to the left:
3(5-x)-((x-1))=0
We add all the numbers together, and all the variables
3(-1x+5)-((x-1))=0
We multiply parentheses
-3x-((x-1))+15=0
We calculate terms in parentheses: -((x-1)), so:We get rid of parentheses
(x-1)
We get rid of parentheses
x-1
Back to the equation:
-(x-1)
-3x-x+1+15=0
We add all the numbers together, and all the variables
-4x+16=0
We move all terms containing x to the left, all other terms to the right
-4x=-16
x=-16/-4
x=+4
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