3(5-z)-23=21z-4(2+6z)

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Solution for 3(5-z)-23=21z-4(2+6z) equation:


Simplifying
3(5 + -1z) + -23 = 21z + -4(2 + 6z)
(5 * 3 + -1z * 3) + -23 = 21z + -4(2 + 6z)
(15 + -3z) + -23 = 21z + -4(2 + 6z)

Reorder the terms:
15 + -23 + -3z = 21z + -4(2 + 6z)

Combine like terms: 15 + -23 = -8
-8 + -3z = 21z + -4(2 + 6z)
-8 + -3z = 21z + (2 * -4 + 6z * -4)
-8 + -3z = 21z + (-8 + -24z)

Reorder the terms:
-8 + -3z = -8 + 21z + -24z

Combine like terms: 21z + -24z = -3z
-8 + -3z = -8 + -3z

Add '8' to each side of the equation.
-8 + 8 + -3z = -8 + 8 + -3z

Combine like terms: -8 + 8 = 0
0 + -3z = -8 + 8 + -3z
-3z = -8 + 8 + -3z

Combine like terms: -8 + 8 = 0
-3z = 0 + -3z
-3z = -3z

Add '3z' to each side of the equation.
-3z + 3z = -3z + 3z

Combine like terms: -3z + 3z = 0
0 = -3z + 3z

Combine like terms: -3z + 3z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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