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3(5a)=((6(30))/2
We move all terms to the left:
3(5a)-(((6(30))/2)=0
determiningTheFunctionDomain 35a-((630/2)=0
We add all the numbers together, and all the variables
35a-(315=0
We add all the numbers together, and all the variables
35a=0
a=0/35
a=0
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