3(5a+4)-20=13a-4

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Solution for 3(5a+4)-20=13a-4 equation: 



3(5a+4)-20=13a-4

We move all terms to the left:

3(5a+4)-20-(13a-4)=0

We multiply parentheses

15a-(13a-4)+12-20=0

We get rid of parentheses

15a-13a+4+12-20=0

We add all the numbers together, and all the variables

2a-4=0

We move all terms containing a to the left, all other terms to the right

2a=4

a=4/2

a=2

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