3(5ax+y)=14ax-4y

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Solution for 3(5ax+y)=14ax-4y equation:


Simplifying
3(5ax + y) = 14ax + -4y
(5ax * 3 + y * 3) = 14ax + -4y
(15ax + 3y) = 14ax + -4y

Solving
15ax + 3y = 14ax + -4y

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-14ax' to each side of the equation.
15ax + -14ax + 3y = 14ax + -14ax + -4y

Combine like terms: 15ax + -14ax = 1ax
1ax + 3y = 14ax + -14ax + -4y

Combine like terms: 14ax + -14ax = 0
1ax + 3y = 0 + -4y
1ax + 3y = -4y

Add '-3y' to each side of the equation.
1ax + 3y + -3y = -4y + -3y

Combine like terms: 3y + -3y = 0
1ax + 0 = -4y + -3y
1ax = -4y + -3y

Combine like terms: -4y + -3y = -7y
1ax = -7y

Divide each side by '1x'.
a = -7x-1y

Simplifying
a = -7x-1y

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