3(5b+2)+b=4(b+9)

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Solution for 3(5b+2)+b=4(b+9) equation: 



3(5b+2)+b=4(b+9)

We move all terms to the left:

3(5b+2)+b-(4(b+9))=0

We add all the numbers together, and all the variables

b+3(5b+2)-(4(b+9))=0

We multiply parentheses

b+15b-(4(b+9))+6=0



We calculate terms in parentheses: -(4(b+9)), so:

4(b+9)

We multiply parentheses

4b+36

Back to the equation:

-(4b+36)



We add all the numbers together, and all the variables

16b-(4b+36)+6=0

We get rid of parentheses

16b-4b-36+6=0

We add all the numbers together, and all the variables

12b-30=0

We move all terms containing b to the left, all other terms to the right

12b=30

b=30/12

b=2+1/2

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