3(5b-4)=72

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Solution for 3(5b-4)=72 equation: 



3(5b-4)=72

We move all terms to the left:

3(5b-4)-(72)=0

We multiply parentheses

15b-12-72=0

We add all the numbers together, and all the variables

15b-84=0

We move all terms containing b to the left, all other terms to the right

15b=84

b=84/15

b=5+3/5

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