3(5c+2)-2c=3(2c+3)+7

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Solution for 3(5c+2)-2c=3(2c+3)+7 equation: 



3(5c+2)-2c=3(2c+3)+7

We move all terms to the left:

3(5c+2)-2c-(3(2c+3)+7)=0

We add all the numbers together, and all the variables

-2c+3(5c+2)-(3(2c+3)+7)=0

We multiply parentheses

-2c+15c-(3(2c+3)+7)+6=0



We calculate terms in parentheses: -(3(2c+3)+7), so:

3(2c+3)+7

We multiply parentheses

6c+9+7

We add all the numbers together, and all the variables

6c+16

Back to the equation:

-(6c+16)



We add all the numbers together, and all the variables

13c-(6c+16)+6=0

We get rid of parentheses

13c-6c-16+6=0

We add all the numbers together, and all the variables

7c-10=0

We move all terms containing c to the left, all other terms to the right

7c=10

c=10/7

c=1+3/7

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