3(5c+3)-28=11c+1

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Solution for 3(5c+3)-28=11c+1 equation:


Simplifying
3(5c + 3) + -28 = 11c + 1

Reorder the terms:
3(3 + 5c) + -28 = 11c + 1
(3 * 3 + 5c * 3) + -28 = 11c + 1
(9 + 15c) + -28 = 11c + 1

Reorder the terms:
9 + -28 + 15c = 11c + 1

Combine like terms: 9 + -28 = -19
-19 + 15c = 11c + 1

Reorder the terms:
-19 + 15c = 1 + 11c

Solving
-19 + 15c = 1 + 11c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-11c' to each side of the equation.
-19 + 15c + -11c = 1 + 11c + -11c

Combine like terms: 15c + -11c = 4c
-19 + 4c = 1 + 11c + -11c

Combine like terms: 11c + -11c = 0
-19 + 4c = 1 + 0
-19 + 4c = 1

Add '19' to each side of the equation.
-19 + 19 + 4c = 1 + 19

Combine like terms: -19 + 19 = 0
0 + 4c = 1 + 19
4c = 1 + 19

Combine like terms: 1 + 19 = 20
4c = 20

Divide each side by '4'.
c = 5

Simplifying
c = 5

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