3(5c+3)=4(c+5)

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Solution for 3(5c+3)=4(c+5) equation:


Simplifying
3(5c + 3) = 4(c + 5)

Reorder the terms:
3(3 + 5c) = 4(c + 5)
(3 * 3 + 5c * 3) = 4(c + 5)
(9 + 15c) = 4(c + 5)

Reorder the terms:
9 + 15c = 4(5 + c)
9 + 15c = (5 * 4 + c * 4)
9 + 15c = (20 + 4c)

Solving
9 + 15c = 20 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
9 + 15c + -4c = 20 + 4c + -4c

Combine like terms: 15c + -4c = 11c
9 + 11c = 20 + 4c + -4c

Combine like terms: 4c + -4c = 0
9 + 11c = 20 + 0
9 + 11c = 20

Add '-9' to each side of the equation.
9 + -9 + 11c = 20 + -9

Combine like terms: 9 + -9 = 0
0 + 11c = 20 + -9
11c = 20 + -9

Combine like terms: 20 + -9 = 11
11c = 11

Divide each side by '11'.
c = 1

Simplifying
c = 1

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