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3(5c-1)=(3c+2)
We move all terms to the left:
3(5c-1)-((3c+2))=0
We multiply parentheses
15c-((3c+2))-3=0
We calculate terms in parentheses: -((3c+2)), so:We get rid of parentheses
(3c+2)
We get rid of parentheses
3c+2
Back to the equation:
-(3c+2)
15c-3c-2-3=0
We add all the numbers together, and all the variables
12c-5=0
We move all terms containing c to the left, all other terms to the right
12c=5
c=5/12
c=5/12
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