3(5c-1)=4(4c+2)

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Solution for 3(5c-1)=4(4c+2) equation:



3(5c-1)=4(4c+2)
We move all terms to the left:
3(5c-1)-(4(4c+2))=0
We multiply parentheses
15c-(4(4c+2))-3=0
We calculate terms in parentheses: -(4(4c+2)), so:
4(4c+2)
We multiply parentheses
16c+8
Back to the equation:
-(16c+8)
We get rid of parentheses
15c-16c-8-3=0
We add all the numbers together, and all the variables
-1c-11=0
We move all terms containing c to the left, all other terms to the right
-c=11
c=11/-1
c=-11

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