3(5c-4)+12=0

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Solution for 3(5c-4)+12=0 equation: 


Simplifying
3(5c + -4) + 12 = 0

Reorder the terms:
3(-4 + 5c) + 12 = 0
(-4 * 3 + 5c * 3) + 12 = 0
(-12 + 15c) + 12 = 0

Reorder the terms:
-12 + 12 + 15c = 0

Combine like terms: -12 + 12 = 0
0 + 15c = 0
15c = 0

Solving
15c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '15'.
c = 0

Simplifying
c = 0

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