3(5d+12)+11d+6=2(d-3)

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Solution for 3(5d+12)+11d+6=2(d-3) equation: 



3(5d+12)+11d+6=2(d-3)

We move all terms to the left:

3(5d+12)+11d+6-(2(d-3))=0

We add all the numbers together, and all the variables

11d+3(5d+12)-(2(d-3))+6=0

We multiply parentheses

11d+15d-(2(d-3))+36+6=0



We calculate terms in parentheses: -(2(d-3)), so:

2(d-3)

We multiply parentheses

2d-6

Back to the equation:

-(2d-6)



We add all the numbers together, and all the variables

26d-(2d-6)+42=0

We get rid of parentheses

26d-2d+6+42=0

We add all the numbers together, and all the variables

24d+48=0

We move all terms containing d to the left, all other terms to the right

24d=-48

d=-48/24

d=-2

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