3(5j+)=2(3j-6)

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Solution for 3(5j+)=2(3j-6) equation: 



3(5j+)=2(3j-6)

We move all terms to the left:

3(5j+)-(2(3j-6))=0

We add all the numbers together, and all the variables

3(+5j)-(2(3j-6))=0

We multiply parentheses

15j-(2(3j-6))=0



We calculate terms in parentheses: -(2(3j-6)), so:

2(3j-6)

We multiply parentheses

6j-12

Back to the equation:

-(6j-12)



We get rid of parentheses

15j-6j+12=0

We add all the numbers together, and all the variables

9j+12=0

We move all terms containing j to the left, all other terms to the right

9j=-12

j=-12/9

j=-1+1/3

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